The Canopy Network Heist
Someone has bypassed the biometric security of the Great Oak Archive and stolen the Prototype Glider Plans! As lead detective of the Canopy Network, you must analyze the physical evidence, track the culprit's flight path, and identify the rogue agent from our roster before they escape the forest canopy.
Possible suspects
Cross off a row as each clue rules it out. On screen, tap a row.
| Name | primary gadget | special escape gear | glove preference | helmet color | allergy trigger |
|---|---|---|---|---|---|
| Agent Ivy | drone controller | smoke pellets | left-handed glove | forest green helmet | oak sap |
| Agent Jax | laser decoder | grapple line | left-handed glove | neon orange helmet | oak sap |
| Agent Fay | climbing spikes | mini glider | left-handed glove | bright blue helmet | oak sap |
| Agent Roy | climbing spikes | rocket boots | left-handed glove | bright blue helmet | oak sap |
| Agent Max | climbing spikes | mini glider | left-handed glove | neon orange helmet | wild berries |
| Agent Cal | drone controller | stealth cloak | left-handed glove | forest green helmet | wild berries |
| Agent Mia | climbing spikes | grapple line | left-handed glove | bright blue helmet | wild berries |
| Agent Eli | grappling sling | smoke pellets | left-handed glove | neon orange helmet | wild berries |
| Agent Sam | grappling sling | smoke pellets | left-handed glove | neon orange helmet | pine pollen |
| Agent Nia | climbing spikes | mini glider | right-handed glove | bright blue helmet | oak sap |
| Agent Jon | sonic jammer | grapple line | left-handed glove | bright blue helmet | oak sap |
| Agent Meg | sonic jammer | smoke pellets | left-handed glove | neon orange helmet | wild berries |
| Agent Dan | climbing spikes | smoke pellets | left-handed glove | forest green helmet | oak sap |
| Agent Kai | drone controller | grapple line | right-handed glove | bright blue helmet | oak sap |
| Agent Ava | climbing spikes | rocket boots | left-handed glove | forest green helmet | oak sap |
| Agent Kim | grappling sling | rocket boots | left-handed glove | forest green helmet | wild berries |
| Agent Leo | sonic jammer | smoke pellets | left-handed glove | bright blue helmet | oak sap |
| Agent Ben | grappling sling | stealth cloak | right-handed glove | neon orange helmet | pine pollen |
| Agent Amy | sonic jammer | stealth cloak | left-handed glove | bright blue helmet | oak sap |
| Agent Eva | sonic jammer | smoke pellets | right-handed glove | forest green helmet | oak sap |
| Agent Joy | sonic jammer | mini glider | left-handed glove | neon orange helmet | wild berries |
Exponents
The security terminal recorded a power surge that multiplied exponentially with each bypass attempt. By solving the power level equation, we can unlock the security footage and narrow down the suspect's gear.
Solve each problem to learn its letter. Then write that letter in every box that shows the same number, and read the secret clue.
Square roots
The thief fled across a perfectly square landing pad at the base of the Great Oak. Knowing the pad's total area, we must find its side length to estimate where the rogue agent made their jump.
Solve each problem to learn its letter. Then write that letter in every box that shows the same number, and read the secret clue.
Pythagorean theorem
To escape, the culprit rigged a secret zip line from the top of the observatory to a distant pine tree. We know the height of the platform and the ground distance, so finding the hypotenuse reveals the speed of their escape.
Solve each problem to learn its letter. Then write that letter in every box that shows the same number, and read the secret clue.
Order of operations
The archive's backup system encrypted its sensor logs with a complex, multi-step math lock. Solving the operations in the correct order reveals the exact physical evidence left at the escape hatch.
Solve each problem to learn its letter. Then write that letter in every box that shows the same number, and read the secret clue.
Two-step equations — the last clue
We tracked the villain's glider speed against the steady headwind blowing through the canyon. Solving this final rate equation pinpointed the exact landing spot and the culprit's allergy triggers.
First solve each problem. Then find each answer in the list below and cross that sentence out. One sentence will be left — that's exactly what the villain did!
Name the culprit
Choose the one suspect left standing.
Answer Key — The Canopy Network Heist
- Clue 1 (Exponents): "THE CULPRIT DOES NOT USE A STEALTH CLOAK"3^2 = 9 (T) · 2^5 = 32 (P) · 17^2 = 289 (O) · 13^2 = 169 (C) · 7^2 = 49 (I) · 2^6 = 64 (D) · 6^3 = 216 (A) · 7^3 = 343 (E) · 14^2 = 196 (N) · 2^3 = 8 (U) · 15^2 = 225 (S) · 18^2 = 324 (R) · 4^2 = 16 (H) · 10^2 = 100 (K) · 5^2 = 25 (L)
- Clue 2 (Square roots): "LEFT GLOVE SCRATCHED THE ARCHIVE LOCK"sqrt(64) = 8 (L) · sqrt(25) = 5 (I) · sqrt(400) = 20 (H) · sqrt(625) = 25 (C) · sqrt(361) = 19 (T) · sqrt(256) = 16 (R) · sqrt(484) = 22 (O) · sqrt(16) = 4 (F) · sqrt(9) = 3 (A) · sqrt(121) = 11 (V) · sqrt(4) = 2 (K) · sqrt(576) = 24 (G) · sqrt(36) = 6 (E) · sqrt(196) = 14 (D) · sqrt(81) = 9 (S)
- Clue 3 (Pythagorean theorem): "THE AGENT WAS ITCHY FROM FRESH OAK SAP"legs 6 and 8, hypotenuse = 10 (T) · legs 24 and 70, hypotenuse = 74 (C) · legs 3 and 4, hypotenuse = 5 (M) · legs 8 and 15, hypotenuse = 17 (Y) · legs 60 and 63, hypotenuse = 87 (S) · legs 20 and 48, hypotenuse = 52 (R) · legs 7 and 24, hypotenuse = 25 (P) · legs 12 and 35, hypotenuse = 37 (N) · legs 25 and 60, hypotenuse = 65 (E) · legs 32 and 60, hypotenuse = 68 (F) · legs 12 and 16, hypotenuse = 20 (I) · legs 30 and 40, hypotenuse = 50 (H) · legs 20 and 21, hypotenuse = 29 (O) · legs 40 and 42, hypotenuse = 58 (W) · legs 5 and 12, hypotenuse = 13 (K) · legs 10 and 24, hypotenuse = 26 (G) · legs 24 and 45, hypotenuse = 51 (A)
- Clue 4 (Order of operations): "BLUE PAINT CHIPS WERE LEFT ON THE BEAM"6 × 2 - 3 = 9 (B) · 10 × 8 - 28 = 52 (U) · 75 + 5 × 8 = 115 (T) · 9 × 7 - 10 = 53 (L) · 10 × 10 - 30 = 70 (H) · 7 + 7 × 4 = 35 (I) · 14 + 3 × 5 = 29 (W) · 11 × 9 - 14 = 85 (M) · 10 + 9 × 2 = 28 (R) · 6 × 9 - 6 = 48 (N) · 17 + 8 × 3 = 41 (E) · 85 + 4 × 2 = 93 (F) · 8 + 6 × 2 = 20 (O) · 52 + 3 × 9 = 79 (S) · 5 × 9 - 28 = 17 (P) · 9 × 11 - 27 = 72 (A) · 10 × 10 - 17 = 83 (C)
- Clue 5 (Two-step equations): surviving statement (box 2) → Agent Roy2x + 4 = 16, x = 6 · 5x + 1 = 16, x = 3 · 6x + 3 = 45, x = 7 · 2x + 4 = 24, x = 10 · 4x + 4 = 48, x = 11 · 2x + 8 = 26, x = 9 · 4x + 7 = 23, x = 4 · 4x + 4 = 8, x = 1 · 2x + 12 = 22, x = 5 · 4x + 3 = 35, x = 8 · 3x + 7 = 43, x = 12
About this mystery
- Grade level
- Grade 8 math
- Math topics
- Exponents, Square roots, Pythagorean theorem, Order of operations, Two-step equations
- Reading level
- grades 7-9
- Theme
- The Canopy Network Heist — set in The Canopy Network
- Format
- Interactive online & printable worksheet with answer key
- Solution
- One unique, verified culprit among 21 suspects
